Question 6

6. Find the pH after 24.90 mL of 0.100 M NaOH has been added to 25.00 mL of 0.100 M HCl.

Finally to calculate the pH, we must:

a) calculate -log

(2.490 x 10

^-3)
b) calculate -log

(1.0 x 10

^-5)
c) calculate -log

{2.490 x 10

^-3 moles} / {0.04990 L}
d) calculate -log

{1.0 x 10

^-5 moles} / {0.04990 L}