11. What is the % ionization for a 0.400M solution of
HN
3
(hydrozoic acid)?
K
a
= 1.9 x 10
-5
We must start with a balanced equation:
a)
HN
3
(aq) + OH
-
(aq)
N
3
-
(aq) + H
2
O (l)
b)
HN
3
(aq)
H
+
(aq) + N
3
-
(aq)
c)
HN
3
(aq) + H
+
(aq)
H
2
N
3
+
(aq)
d)
HN
3
(aq) + H
2
O (l)
H
2
N
3
O (aq) + H
+
(aq)
