15. What is the % ionization for a 0.400M solution of HN3 (hydrozoic acid)? Ka = 1.9 x 10-5

Balanced equation: HN3 (aq) H+ (aq) + N3- (aq)

I.C.E. grid:

HN3 (aq) H+ (aq) N3- (aq)
INITIAL
0.400M
0M
0M
CHANGE
-xM
+xM
+xM
EQUILIBRIUM

What are the equilibrium concentrations of each of the species?

a) (0.400-x)M, xM, xM
b) (0.200-x)M, xM, (0.200+x)M
c) xM, 0M, (0.400-x)M
d) (0.400-x)M, (0.400-x)M, (0.400-x)M