3. What is the pH of a solution of 0.200 M H3C6H5O7 (citric acid)? Ka = 3.5 x 10-4

We must always start with a balanced equation, so what is the ionization equilibrium for citric acid?
a) H3C6H5O7 (aq) + H2O (l) H+ (aq) + H5C6H5O8- (aq)
b) H3C6H5O7 (aq) + H2O (l) H4C6H5O7+ (aq) + OH- (aq)
c) H3C6H5O7 (aq) H+ (aq) + H3C6H4O7- (aq)
d) H3C6H5O7 (aq) H+ (aq) + H2C6H5O7- (aq)